Help on angular acceleration problem given mass and angle?

Question

A rod with mass M = 1.3 kg and length L = 0.98 m is mounted on a central pivot. A metal ball of mass m = 0.70 kg is attached to one end of the rod. You may treat the metal ball as a point mass. The system is oriented in the vertical plane and gravity is acting. The rod initially makes an angle θ = 26° with respect to the horizontal. The rod is released from rest. What is the angular acceleration of the rod immediately after it is released?

Picture to go with problem: http://i284.photobucket.com/albums/ll28/bathtub2008/showmepl-4.gif

α = _____ rad/s2

Answer 1

I = Ir + Ib = (1/12)ML² + m*R² = .272 kg∙m²

α = T/I = mgx/I = mg(.49cos26°)/I = 11.107 rad/s²

Answer 2

x = mc2 x 3.14 = a+b+c= the sqare root of nebula