Help please! I am not getting these college algebra problems!?

Question

Simplify the expression .

55

___

35

Simplify the following expression. This is one of the hardest

B^2 +5b+6

__________

3bc

_______

b^2-9

______

6bc

Solve this proportion for the variable:

3/y=12/8

If you answer each of these questions with separate replies it will give you more points. Thanks for your help!

Answer 1

On second thought please do them yourself. You are hurting your understanding

Answer 2

B^2 +5b+6

= (b+3)(b+2)

3bc

=(3)(b)(c)

b^2-9

(b-3)(b+3)

6bc

=(3)(2)(b)(c)

3/y=12/8

= y=2

Answer 3

11/7

write it correctly

2

Answer 4

55 / 37 = 11 / 7

[(b^2 + 5b + 6) / (3bc)] / [(b^2-9) / (6bc)]

[(b^2 + 5b + 6) / (3bc)] * [(6bc) / ( b^2 - 9)]

[(b + 3)(b + 2) / (3bc)] * [(6bc) / (b + 3)(b-3)]

[(b + 2) / (1)] / [(2) / (b - 3)]

(b+2)(2) / (b -3)

(2b + 4) / (b - 3)

3 / y = 12 / 8

12y = 24

y = 2

These are simple algebra problems. The second problem is known as a complex fraction since it is a fraction over a fraction. All you have to do is just take the numerator of the complex fraction and multiply it by the opposite of the denominator.

Answer 5

11/7

{(b+3)(b+2)/3bc}/{(b+3)(b-3)/6bc = 2(b+2)/(b-3)

12y = 24; y = 2