Question:

Help please? stuck on algebra?

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Solve each equation for x. Find any restrictions.

1) bx - cx = -c

2) a/x - 5 = b

THANK YOU =D

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7 ANSWERS


  1. 1)

    bx - cx = -c

    x(b - c) = -c

    x = -c/(b - c) (b ≠ c)

    2)

    a/x - 5 = b

    a/x = b + 5

    x = a/(b + 5) (x ≠ 0)


  2. 1. x= -c/(b-c)

    2. x= a/(b+5) or x= (a - 5)/b

  3. 1) x cannot equal 0


  4. 1) (b-c)x = -c

        x = -c/(b-c)

        b - c not equal to 0 therefore b can not equal c

    2) a/x - 5 = b

        a/x = b+5

        a/(b+5) = x

        b can not equal -5


  5. bx - cx = -c, grouping the term 'x' we have...

    x (b-c) = -c, dividing throughout by (b-c) we will get...

    x = -c / (b-c), there is no restriction on x here, meaning that x can take on any values as long as it is able to satisfy the equation.

    a/x - 5 = b, since x is in the denominator, we must remember that if x is 0 then the equation will blow out of proportion since anything divided by 0 is infinity and infinity is BAD:)

    making x the common denominator in the leftHandSide, we get...

    (a-5x) / x = b, cross multiply x over to the rightHandSide,

    a-5x = bx, grouping the 'x' terms we have...

    a = bx + 5x = (b+5)x, dividing throughout by (b+5) we will get...

    x = a / (b+5), where x CANNOT take the value of zero

    cheeers!~


  6. 1)  x(b-c) = -c

          x = -c/(b-c)  Restriction:  b does not equal c

    2)  a/x = b+ 5

          x/a = 1 / (b+5)

            x  =  a / (b+5)  Restrictions:  a does not equal zero AND b does

                                                       not equal -5

    ANSWER

  7. 1) bx - cx = -c

       x (b - c) = -c

       x = -c / (b-c)

    2) a/x - 5 = b

        ----------------------- *x

       a - 5x = bx

       a = bx + 5x

       a = x (b +5)

       x = a / (b+5)

    Thank you. ^^  

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