Help pleaseA liquid has delta Hvap of 44.0 kJ/mol and a vapor pressure of 370 torr at 90 centigrade what is

Question

the vapor pressure of the liquid at 130 degree centigrade

Answer 1

Clausius-Clapeyron equation

where

T1 and P1 are a corresponding temperature (in kelvin) and vapor pressure

T2 and P2 are the corresponding temperature and pressure at another point

ΔHvap is the molar enthalpy of vaporization

R is the gas constant (8.314 J mol-1K-1)

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ln(P2/P1)= (dH / R) (1/T1 - 1/T2)

ln(P2/ 370)= (44,000j / 8.314) (1/363K - 1/403K)

ln(P2/ 370)= (44,000j / 8.314) (0.002755 - 0.002481)

ln(P2/ 370)= (5292.3)(2.74e-4)

ln(P2/ 370)=1.429

e^x both sides

P2/370 = 4.174

P2 = 4.174 (370) = 1544 Torr

your answer (3sigfigs): 1540 Torr