Help solve 3x + 2y = 14 & 3x - 2 = 10?

Question

solve system by the addition method

Answer 1

3X - 2 = 10  *[+2]

3X = 12

X=4

3X+2Y = 14

3(4) + 2Y =14  *[-12]

[12]

2Y = 2

Y= 1

Answer 2

solve for x in both equations

1) 3x+2y=14

3x=14-2y

x=(14-2y)/3

2) 3x-2=10

3x=12

x=4

sub in #2 into #1 to get :

4=(14-2y)/3

12=14-2y

-2=-2y

y=1

so x=4 and y=1

who says hockey players arent smart??? hopefully i can still do this, i mean i am in calc III right now....ahhaha

Answer 3

3x-2=10

Add two to both sides to make

3x=12

Then divide both sides by 3 to make

x =4

Substitute that into the first problem

3(4)+2y=14

Multiply 3 times 4

12 +2y =14

Subtract 12 from each side

2y=2

Divide each side by two

y=1

x=4

Answer 4

First solve for x. 3x-2+2=10 + 2. 3x/3=12/3. x=4. Plug the value of x in the first equation. 3(4) + 2y= 14. 12+2y-12=14-12. 2y/2=2/2. y=1, and x=4.  

Answer 5

Have an expansion draft.

Answer 6

Jello?

Answer 7

Wrong... x=-5 and y= 16

I'd show the work, but I did it in my head

Answer 8

nice hockey question!

junior hockey starts in 19 days!!

Answer 9

x = 4

y = 1

Answer 10

Well.....x is 4 and y is 1. Sorry, but i don't remember algebra enough to really do it using the addition method. What I did to solve it though is that if 3x - 2 = 10, then 3x - 2 (+2) = 10 (+2), so 3x = 12 and x = 4. Then I substituted x for 4 in 3x + 2y = 14, to get 12 + 2y = 14. Subtract 12 from both sides to get 2y = 2, and y = 1. I'm not sure if that's really what you were looking for, but at least I gave you the answer, right?