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Help solve this fraction question?

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Appreciate any help solving this problem

1/a = 1/b+c. Solve the fraction in terms of a (final answer should have a on one side and all other variables on the other side)

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  1. 1/a = 1/b + c

    1/a = (1 + cb)/b

    Now take the reciprocal of both sides:

    a = b/(a + cb)

    If it's :

    1/a = 1/(b + c)

    Then just take the reciprocal:

    a = b + c


  2. You need to be clearer in your problem statement:

    Is it 1/(b+c) or (1/b) + c?

    If it is 1/a = (1/b)  +  c

    Then it is

    1 = (b/a) - bc

    If it is 1/a = 1/(b+c)  then the solution is

    1 = (b+c)/a

  3. 1/a = 1/b+c

    a = b+c

  4. the numerators are equal so the denominators are equal.

    a = b + c

  5. its simple

    a= b+c

    :)

  6. assumming: 1/a = 1/(b+c) {cross multiply }

    a *1 = 1*(b+c)

    a= b+c {answer}

    assumming:

                 1/a = 1/b +c

                  a(1/a) = a(1/b +c) {multiply both by 'a'}

                    a/a   = a(1/b +c) {a/a =1}

                    1     = a(1/b +c)   {divide both by (1/b +c)}

                    1/(1/b +c) =a

                     b+ 1/c =a    {solution}

    good catch minorchord!

  7. 1= a/(b+c)

    a = b+c

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