Help solving this math problem?

Question

I have tried and tried and can't not figure out how to do this.. Any help would be appreciated!

Solve by elimination method

p=25+q

6p= -3q+204

What is the solution of the system, type an ordered pair?

Answer 1

it is simple to solve

multiply first eq with 6

u will get

6p=150+6q

then subtract eq2 from newly drived eq

6p=150+6q

+6p=204-3q

-      -     +

0=-54+3q

or q=18

put value of q in any eq  and get value of p

Answer 2

you have to get the q by itself in the second equasion and compare the two equasions for the value of p versus the value of q

Answer 3

If p is 25+q then you instert that wherever p is.I think you might get it from there.

Answer 4

I dont know WHY you would solve this in elimination method, that is OBVIOUSLY not the easiest way to solve it. just move p=25+q, move q to the other side so you get p-q=25 then multiply q by -3 and then add the two equations  

Answer 5

P=30

q=8

6p=-3q+204

6 times 30 = -3 times 8 + 204

180= -24 + 204

180 =180

Answer 6

6*(25+q)=-3q+204

150+6q=-3q+204

6q+3q=204-150

9q=54

q=6

p=25+6=31