Help these mothers save their babies?can u?

Question

2 moms, 3 babies and 2 tigers been traveling until they reached a point where the can only cross by a small both that can only transport 2 things at same time or it will sink. there r two witches at both ends that will eat any child if left alone.the tigers too will eat the babies in the absent of any of the mothers. help them cross safe without any loss?

Answer 1

VERY SIMPLE. the question said:help these mothers save thier babies which means that the loss of the two tigers does not really matter.

here is how it goes, mother and tiger first,  mother come back take another tiger, two babies cant ride, it means one can ride, then mother bo back, mother and baby come over, followed by a baby then, lastly, mother and baby.

this is a very critical question which involves paying close attention to the question and not the solution or answere. fellas pls rate my idea

Answer 2

intresting...........................

but i dunno

Answer 3

if the tigers will eat the baby in absence of ANY mother,

then this situation is impossible to solve

lol boxer lover you have talented babies who can operate boats *clap clap*

wow and now indian hippy presents us with super tigers who can operate boats. Marvelous

Answer 4

First the tigers will go and one tiger will come back.Then a mother and a tiger will go.The mother will come back and take a baby and go.The baby will come back and take one more baby and go and again one of the baby will come back  and take the last baby and go to the other side.Then again one baby will go back take the mother(who is the last one)and they both will go the other side.

                                          OR

First the mother will go alone to the other side and and beat the h**l out of the witch and take her to the 1st side.Then the mother will come and take a baby and go to the other side and come back and take another baby then got to the other side and yet again come back take another baby then go to the other side and come back take the 2nd mother(Two mothers i think they are lesb*) to the other side and then one of the mother will come and take the tiger and go back to the 2nd side and then come again take the last tiger and they all go.

Answer 5

First goes the mother and tiger. Then goes 2 babies, then another mother with a baby. and the tiger comes last...

That way the babies arent left with the tigers and arent alone.

Answer 6

it has to go front and back, doesn't it?

Okay.

mom = M

baby = B

tiger = T

M + B go to the other side. (M,T,T,B,B) - (M,B)

B comes back. (M,T,T,B,B,B) - (M)

T + T go to the other side. (M,B,B,B) - (M,T,T)

T comes back. (M,B,B,B,T) - (M,T)

2 Bs go to the other side. (M,T,B) - (M,B,B,T)

1 T comes back. (M,T,T,B) - (M,B,B)

2 Ts go to the other side. (M,B) - (M,B,B,T,T)

1 T comes back. (M,B,T) - (M,B,B,T)

1 T goes to the other side. (M,B) - (M,B,B,T,T)

1 M and 1 B go to the other side. () - (M,B,B,B,T,T)

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