Help with Algebra and parabolas ?

Question

6x^2 + x = 2

I started solving but I am not sure.. Please help and show work

3x^2 + 10x + 5 = 0 I am also having the same issue with this equation

Answer 1

First one:

6x^2 + x - 2 = 0

(3x + 2)(2x -1) = 0

x = -2/3, 1/2

Second one use the quadratic formula. Which is a pain to type out here. Look in the sources for the formula.

Answer 2

i give you a link so you can study how to solve this easily

http://www.josechu.com/ecuaciones_polino...

read in the section "second degree equation (or quadratics)"

Answer 3

6X^2 + X = 2

First get the equation to equal zero

6X^2 + X - 2 = 0

This one will break into factors pretty easily if you just work with it for a few minutes.

(3X + 2) (2X - 1) = 0

Then set each factor equal to zero and solve

3X + 2 = 0

3X = -2

X = -2/3

2X - 1 = 0

2X = 1

X = 1/2

So you're answer is X = -2/3 , 1/2

For the second one, you can't factor it yourself, you have to use the quadratic formula.

Answer 4

these r hard and ugly...sory but i tried but i had algebra last year and i cnt really remember how 2 solve these thingies

Answer 5

Both can be solved with the quadratic formula:

x=[-b +/- sqrt(b^2-4ac)]/2

Only the first one can be solve without the formula:

(3x+2)(2x-1) = 0

Answer 6

Hey  yunge, this a simple equations & u slove it by Algebra.

6x^2+x =2   or  6x^2+x-2 =0 Now u use "SHRIDARACHARYA RULE"

    then u get solution x= -1+7/12 = 6/12 =1/2 =0.5

                                      x= -1-7/12  =-8/12=-2/3

  

3x^2+10x+5 =0  or   x =-10+2{10}/6

                                     x=-10-2{10}/6             {}= Under root

u get exact answer of ur first equ... but u can't get exact answer of ur second equ............