Help with Algebra review packet problem?

Question

I can't for my life figure out how to get this into an equation- I don't need help solving it once it's in the form of a/n equation(s):

Sauder has three times as much money as Sony. Sammy has $4 less than Sauder and $5 more than Sony. How much money does each have.

Any help would be more than appreciated.

Answer 1

sauder = a

sony=b

sammy=c

..Sauder has three times as much money as Sony..so the first equation is A=3b

Sammy has $4 less than Sauder c+4=a

Sammy has $5 more than Sony b+5=c

..By what we have so far We know that 3b=c+4

b = c-5 also so substitute b into the above equation we have 3(c-5)=c+4.....that's 3c-15=c+4....c=$9.5

...if c= 9.5 then a=9.5+4=$13.5

then b=9.5-5=$4.5

so Sauder has $13.5

Sony has $4.5

and Sammy has $9.5

I know it's messy but hope you understand

Answer 2

Let x = Sauders money, y = Sony's z = Sammy's

x = 3y

z = x-4

z = y + 5

I imagine you got this far so I'll take you further...

x-4 = y + 5

You can substitue for x now so you only have y in the equation. form there is it just solving for y then finding the other two.

Care to return the favor?

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