Help with Quadratic Functions?

Question

x^2 + 6x + 16

i'm confused cause it can't be factored. and whats the axis of symmetry (how do you find it?)

Answer 1

u need to find x first of all by using x= -b±√d divided by 2

d= b^2-4ac

d=6^2-4(1)(16)

d=36-64

d=(-28)

This parabola has not solution because there's not square root of a negative number. If you find a imaginary solution you have

√7*√-1 or i*√4

4i√7

go back to the quadratic formula

-6±4i√7

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   2

or negative 6 plus/minus 4i square root of 7 divided by 2. this parabola only has imaginary solutions.

The axis of symmetry is

x=-b/2(a)

x=-6/2

x= -3

thats where the axis of symmetry is. The parabola opens upwards and it has  no zeros.

Answer 2

axis of symmetry is through the vertex

so the x xcoordinate  of symmetry is found by x = -b/2a

= -6/2*1

-3

so axis of symmetry is where x=-3 a vertical line.