Help with algebra problem?!?

Question

The problem is this equation:

11-x/3x+2=1/2

Its due tomorrow! Thanks!

Answer 1

I'm rewriting your equation with parentheses to make it clearer

(11 - x)/(3x + 2) = 1/2

Multiply each side by (3x + 2) to get...

(11 - x) = 1/2*(3x + 2)

Distribute the 1/2....

11 - x = 3/2x + 1

Add x to each side

11 = 5/2x + 1

Subtract 1 from each side

10 = 5/2x

Divide each side by 5/2

4 = x

Checking the original equation

(11 - 4)/(3*4 + 2) = 1/2

7/(12 + 2) = 1/2

7/14 = 1/2

1/2 = 1/2  CHECK

The answer is...

x = 4

Answer 2

11-x

------  =   1/2

3x+2  

times both sides by 2to get rid of the fraction on the right hand side

22-2x

--------  =   2

6x +4

times both sides by 6x + 4 to eliminate the fraction on the left hand side

22 - 2x =  12x + 8

minus 8 from both sides to try and get x by itself

14 - 2x = 12x

minus 2x from both sides to get x on one side of the equation

14 = 14x

divide both sides by 14 to get x by itself

x = 1

Answer 3

Very well,it's easy...just multiply the extremities(like this)

11-x/3x+2=1/2==>

3x+2=2(11-x)==>

3x+2=22-2x==>(we take the -2x from the right side and add 2x to the 3x in the left side due to the opposite sign convention)

This means==>5x+2=22(subtract)==>5x=20==>x=4

Excuse but I'm not familiar to explaining math in english...hope this helped