Help with maths! if y = 3.227x^2 +5.001x + 3.435, what is the vaue of x for this equation?

Question

and please show your workings so i can complete other questions by myself thank

Answer 1

You have the equation equal to y.  In that case, x can be ANY number or value since you do not specify any constraints on your variables.

The only thing that could be said is that all values of y depend on what you put in for x.

Now if you were to say that y equals 0 or you are trying to find the zeros of the equation, then the easiest way would be to use the quadratic formula.

x = [-b ± √(b² - 4ac)] / 2a, where a = 3.227, b = 5.001, c = 3.435

x = [-5.001 ± √(5.001² - 4*3.227*3.435)] / 2*3.227

x = [-5.001 ± √(25.010001 - 44.33898)] / 6.454

x = [-5.001 ± √(-19.328979)] / 6.454