Help with negative exponents?

Question

here's the problem: (5 x^-3 y^-2 / 3 x^2 y^-3) ^-2

Answer 1

(9/25)*x^10 y^-2

Answer 2

(5x^-3y^-2/3x^2y^-3)^-2

= 1/(5x^-3y^-2/3x^2y^-3)^2

= 1/[5^2x^(-3 * 2)y^(-2 * 2)/3^2x^(2 * 2)y^(-3 * 2)]

= 1/[25x^-6y^-4/9x^4y^-6]

= 1[(9x^4/y^6)/(25/x^6y^4)]

= (9x^4/y^6)/(25/x^6y^4)

= (9x^4/y^6)(x^6y^4/25)

= 9x^10y^4/25y^6

= (9/25)(x^10)(y^4/y^6)

= (9/25)(x^10)(y^-2)

= 9x^10/25y^2

Answer 3

With negative exponents you take the expression to the power

and then take the reciprocal.

i.e.  

        x^ -3   =  1 / x^3.

Answer 4

5^(-2) x^6 y^4

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3^(-2) x^(- 4) y^(6)

9 x^(10)

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25 y ²

Answer 5

y^-3 means -y times -y times -y you just make it negative