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Help with pre calculus?

by Guest57767  |  earlier

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Find the value of h if the line joining (7,h) and (2,-5) is parallel to the line y=7x-5.

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  1. Two parallel lines have the same slope

    The slope of y = 7x -5 is 7.

    Solve for m:

    m = (y2 - y1)/(x2-x1) = 7

    =(-5 - h) / (2 - 7) = 7

    =-5-h/-5 = 7

    =5-h/5 = 7

    5-h = 35

    -h = 30

    h = -30


  2. You need to have the same slope = 7 for the lines to be parallel.

    So since your x rises 5 points.

    h = 5 * 7 - 5 = 30

    So Point (7,30)

  3. First of all..the line is parallel so that means the slope would stay the same.

    Then use the slope equation

    y2 - y1 = m (x2 - x1)

    -5 - h = 7 (2 - 7)

    -h = -35 + 5

    h = 30

    Hope this helps :)

  4. Seeing as the line is parallel, it would have the same slope as the equation given, which is 7.

    Now, using the slope formula, knowing the slope is 7:

    (-5 - h) / (2 - 7) = 7

    Cross multiply:

    7(2 - 7) = -5 - h

    -35 = -5 - h

    -30 = h

    h = 30

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