Help with probability please? Thanks?

Question

1. We toss three coins. What is the probability of the event "3 Heads appear"?

2. We perform the experiment "Toss two dice". What is the probability of the event "the sum of the faces equals 5"?

3. We perform the experiment "deal a five card poker hand". What is the probability that you are dealt a hand that contains the Ace, Two, Three, and Four of Diamonds?

Most thorough answer will be awarded best answer ASAP! Thanks again for all your help! :)

Answer 1

Good job red vee - thumbs up!

King Cobra Poker

Answer 2

1. Probability of getting Heads is 1/2. The probability of getting three heads in a row is therefore 1/2 x 1/2 x 1/2 = 1/8.

2. Two dice give 36 combinations. For the sum to be 5, the possibilities are 1,4 or 4,1 or 2,3 or 3,2. There are therefore 4 chances out of the 36 that the sum of the faces equals 5. So the probability is 4/36 or 1/9.

3. Assuming you're dealing from 1 pack of cards, the probability of being dealt that hand can be calculated like this: the first card can be any one of the five, drawn from the 52; the second can be any of the remaning four cards drawn from the 51 etc. So the probability is given by the equation: 5/52 x 4/51 x 3/50 x 2/49 x 1/48 = 120/311875200 which equates to 0.0000003847. In fact, this is the probability of getting ANY specific hand in poker and is calculated as 1/2,598,960 (the total number of 5 card hands)

Answer 3

red vee is right in everything but number three

im not going to do the math but you must do a choose set up. it would look like

52c1*51c1*50c1*49c1*48c1

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52c5

if i remember correctly

Answer 4

I don't deal with probabilities.  I just bet on whatever my trusty 97% WIN guide tells me.  More info?  http://johnmorrisonsystem.wordpress.com