Help with probability??

Question

Find the probability to get exactly one 6 in four throws with an ordinary die.

Answer 1

There are four ways to get exactly one 6 in four throws, each having the same probability: first throw is a 6, the rest aren't, or the second throw is a 6, the rest aren't, etc.

The probability of rolling a 6 on any roll is 1/6, and the probability of rolling anything other than a 6 is 5/6. So the probability of rolling a 6 on your first roll and no other 6's is (1/6)(5/6)^3. Similarly for the other 3 cases.

So in total you have 4(1/6)(5/6)^3

Answer 2

4c1*1/6*(5/6)^3=4*1/6*5^3/6^3=4*125/6^4=...

Answer 3

Hi,

4nCr1(1/6)^1(5/6)^3 = .3858

The probability to get exactly one 6 in four throws with an ordinary die is 38.58%. <==ANSWER

I hope that helps!!