Question:

Help with this math please?

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1: Rationalize these radical expressions:

sqrt 45/ sqrt 5

2: sqrt 35/ sqrt 7

3: sqrt 6x/7

4: sqrt 45x^2/ sqrt 9

5: sqrt 14x/18x

6: sqrt 75xy^7/12xy

7: sqrt 2x/9x

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  1. I'll do the first one, since the steps are all similar, you should be able to do the rest:

    √45 / √5

    You want to remove the radical from the denominator.  So multiply both sides of the fraction by √5, and this happens:

    √(45) √(5) / [√(5) * √(5) ]

    since 45 = 9 * 5:

    √9 * √5 * √5 / 5

    3 * 5 / 5

    3


  2. sqrt 45/ sqrt 5= sqrt(45*5)/5=(sqrt225)/5=15/5=3

    2: sqrt 35/ sqrt 7=sqrt245/7=7sqrt5/7= sqrt5

    3: sqrt (6x/7)=sqrt(42x)/7

    4: sqrt 45x^2/ sqrt 9=3x sqrt5/3=x sqrt5

    5: sqrt(14x/18x)= sqrt(7/9)= sqrt(7)/3

    6: sqrt (75xy^7/12xy)=[5y^3 sqrt(3)]/2sqrt3=5y^3/2

    7: sqrt (2x/9x)= (sqrt2)/3

  3. √45/√9=√45/9 = √5

    √35/√7=√35/7=√5

    3cant do anything

    √45√x^2/√9 = x√9√5/ √9 = x√5

    √14x/18x = √ 7/√9 = √7/3

    √75xy^7/√12xy = √25√3√x√y^6√y / √4√3√x√y

    = 5y^3/2

    √2x/√9x

    √2/(3)

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