Help with this motion physics problem please?

Question

A bushwalker climbs a hill 250 m high. If her mass is 50kg and her pack weighs an additional 10kg, calulate the work she needs to do in climbing the hill.

thanks heaps!

Answer 1

Work is the scalar product of force and distance. In this case,

W = mgh = ( 60 kg ) ( 9.8 m/s² ) ( 250 m ) = 147,000 J.

Answer 2

Work done in raising any body to a certain height is given by the formula W = mgh

so m = 50 + 10 = 60 kg

W = 60*9.8*250 = 147000 Joules.

Answer 3

Work = Force x Distance

The force of gravity of the person with the pack is:

F = mg = (50 kg + 10 kg) x 9.8 m/s² = 588 N

The work is:

W = Fd = 588 N x 250 m = 1.47 x 10^5 J