Help with two problems! Thanks?

Question

y-1/z=3 .. solve for m (isolate m)

xy^2 + z^3 = 1 solve for x (isolate x)

Answer 1

for the first one is it (y-1)/z=3 or y-(1/z)=3?

and there is no m in the problem, so you cant isolate something that isnt there!

for the second one

xy^2 + z^3 = 1 move z^3 to the other side

xy^2= 1- z^3

square root both sides

xy= sqrt(1-z^3) divide by y

and you have

x=(sqrt(1-z^3))/y

Answer 2

TT Hi !!

y-1/z=3 .. solve for z (isolate z)

y-1 = 3z

z = (y - 1)/3 ◄ Ans

xy^2 + z^3 = 1 solve for x (isolate x)

xy² + z³ = 1

xy² = 1 - z³

x = (1 - z²)/y² ◄ Ans

hope this helps

Answer 3

y-1/z=3, there is no m to solve for...

xy^2+z^3=1

xy^2=1-z^3

x=(1-z^3)/y^2