Question:

Hexagon, how to figure?

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An area of 9ft.x11ft., how do I figure the area for a hexagon

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  1. The area of a regular hexagon with sides t is 3 sqrt ( 3 ) t² / 2.

    To find the area of an irregular hexagon such as the one you describe requries far more information than you provide.


  2. You must state clearly that it is a regular hexagon.

    Let a be the length of a side,then

    the total areas of the 6 identical triangles of base a=

    99 sq.ft.

    Let the height of a triangle be h measured from the base,then

    h=a*tan60*/2=>

    h=(3^1/2)a/2 ft.

    (6/2)ah=99=>

    3(3^1/2)a^2/2=99=>

    a^2=22(3^1/2)=>

    a=6.17 ft.(correct to 2 decimal places)

    So,the hexagon can be constructed with a


  3. Sorry, your question does not make any sense.  An area of 9 x 11 does not translate to: how do I find the area for a hexagon.  Check your source.

  4. Ooooo!! a hexagon has 6 sides!!!!!!!!!!!!!!

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