Hey guyz. I'm writing a java code and...?

Question

Hey guyz. I'm writing a java code and i wanna know if there's a shorter way to write this code below. thanks.

for(i = 0; i < s.length(); i++)

{

aChar = s.charAt(i);

switch(aChar)

{

case'a': aChar = theKey.charAt(0); break;

case'A': aChar = theKey.toUpperCase().charAt(0); break;

case'b': aChar = theKey.charAt(1); break;

case'B': aChar = theKey.toUpperCase().charAt(1); break;

case('c'): aChar = theKey.charAt(2); break;

case('C'): aChar = theKey.toUpperCase().charAt(2); break;

case('d'): aChar = theKey.charAt(3); break;

case('D'): aChar = theKey.toUpperCase().charAt(3); break;

case('e'): aChar = theKey.charAt(4); break;

case('E'): aChar = theKey.toUpperCase().charAt(4); break;

case('f'): aChar = theKey.charAt(5); break;

case('F'): aChar = theKey.toUpperCase().charAt(5); break;

case('g'): aChar = theKey.charAt(6); break;

case('G'): aChar = theKey.toUpperCase().charAt(6); break;

case('h'): aChar = theKey.charAt(7); break;

case('H'): aChar = theKey.toUpperCase().charAt(7); break;

case('i'): aChar = theKey.charAt(8); break;

case('I'): aChar = theKey.toUpperCase().charAt(8); break;

case('j'): aChar = theKey.charAt(9); break;

case('J'): aChar = theKey.toUpperCase().charAt(9); break;

case('k'): aChar = theKey.charAt(10); break;

case('K'): aChar = theKey.toUpperCase().charAt(10); break;

case('l'): aChar = theKey.charAt(11); break;

case('L'): aChar = theKey.toUpperCase().charAt(11); break;

case('m'): aChar = theKey.charAt(12); break;

case('M'): aChar = theKey.toUpperCase().charAt(12); break;

case('n'): aChar = theKey.charAt(13); break;

case('N'): aChar = theKey.toUpperCase().charAt(13); break;

case('o'): aChar = theKey.charAt(14); break;

case('O'): aChar = theKey.toUpperCase().charAt(14); break;

case('p'): aChar = theKey.charAt(15); break;

case('P'): aChar = theKey.toUpperCase().charAt(15); break;

case('q'): aChar = theKey.charAt(16); break;

case('Q'): aChar = theKey.toUpperCase().charAt(16); break;

case('r'): aChar = theKey.charAt(17); break;

case('R'): aChar = theKey.toUpperCase().charAt(17); break;

case('s'): aChar = theKey.charAt(18); break;

case('S'): aChar = theKey.toUpperCase().charAt(18); break;

case('t'): aChar = theKey.charAt(19); break;

case('T'): aChar = theKey.toUpperCase().charAt(19); break;

case('u'): aChar = theKey.charAt(20); break;

case('U'): aChar = theKey.toUpperCase().charAt(20); break;

case('v'): aChar = theKey.charAt(21); break;

case('V'): aChar = theKey.toUpperCase().charAt(21); break;

case('w'): aChar = theKey.charAt(22); break;

case('W'): aChar = theKey.toUpperCase().charAt(22); break;

case('x'): aChar = theKey.charAt(23); break;

case('X'): aChar = theKey.toUpperCase().charAt(23); break;

case('y'): aChar = theKey.charAt(24); break;

case('Y'): aChar = theKey.toUpperCase().charAt(24); break;

case('z'): aChar = theKey.charAt(25); break;

case('Z'): aChar = theKey.toUpperCase().charAt(25); break;

}

aString += aChar;

}

Answer 1

Yes, there is.

First, use Character.toUpperCase instead of converting the entire string to uppercase every time you encounter an uppercase character.

Second, you can use some character arithmetic to simplify it a bit more.

Third, tertiary-ifs are awesome, and should be used at every opportunity.

Fourth, rewriting 85-lines of code as one statement is cool and should also be done at every opportunity, even if the result is neigh unreadable. Trust me, I&#039;ve been doing this for a while.