Question:

Hey simplifying one algebra problem?

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-5/12 + 1 5/8 + (-6 3/10)

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  1. To add fractions they need to have a common denominator

    -5/12 =[ 10 * (-5) ] / (10 * 12) = -50/120

    1 5/8 = 13/8 = (15 * 13) / (15 * 8) = 195/120

    -6 3/10 = -63/10 = (12 * (-63)) / (12 * 10) = -756/120

    -5/12 + 1 5/8 + (-6 3/10) =

    -50/120 + 195/120 - 756/120 =

    (-50 + 195 - 756)/120 =

    -611 / 120 =

    -5 11/120


  2. convert all the denominators to the same thing:

    -100/240 + 240/240 + 150/240  -1440/240 - 72/240 = -1022/240

    Simplify: -1222/240 = -611/120

  3. -5/12 + 1 5/8 + (-6 3/10)

    Change to all fractions (not mixed):

    = -5/12 + 13/8 - 63/10

    Find LCD:

    12 = 2 x 2 x 3

    8 = 2 x 2 x 2

    10 = 2 x 5

    LCD = 2 x 2 x 2 x 3 x 5 = 120

    -5/12 = -50/120

    13/8 = 195/120

    -63/10 = -756/120

    -50/120 + 195/120 - 756/120

    = (-50 + 195 - 756)/120

    = -611/120

    = -5 11/120

  4. -5/12 + 1 5/8 + (-6 3/10) (change mixed numbers to improper fractions)

    -5/12 + 13/8 - 63/10 (find the least common denominator of 12, 8, and 10, which is 120)

    -5/12*10/10 + 13/8*15/15 - 63/10*12/12

    -50/120 + 195/120 - 756/120 (add and subtract numerators)

    -611/120 or -5 11/120 <===ANSWER

  5. You have to find a common denominator. I believe the answer is -307/60

  6. 12=3*2*2

    8=2*2*2

    10=5*2

    then you need 5*3*2*2*2=10*12=120

    You will multiply by

    120/12=10

    120/8=40*3/8=5*3=15

    120/10=12

    -50/120 + 1 75/120 + (-6 36/120)

    Separate the integers

    1-6 + (75-50-36)/120 = -5 - (11/120)

    =- 5 11/120 = -611/120

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