Question:

Hi there I having an Algebra Money Mixture Problem I can't figure out? Help!?

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Tom invested $11,000, part at 9% and part at 10% simple interest. How much money was invested at each interest rate if the total interest earned from both is $1050?

HI there how do I solve this and whats the answer, Is there a formula for this.

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  1. 1050 = .09x + .1(11000 - x)

    1050 = .09x + 1100 - .1x

    -50 = -.01x

    x = 5000

    $5,000 @ 9%

    $6,000 @ 10%

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