Question:

High calcium chloride react with lower sodium carbonate?

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If a high volume of calcium chloride reacts with lowerl volume of sodium carbonate

what is formed?

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  1. cacl+naco3---->nacl+caco3


  2. CaCl2(aq) + Na2CO3(aq) --> CaCO3(s) + 2NaCl(aq)

    It makes no difference what the volumes of solutions are that you mix. The reaction occurs according to the stoichiometry show above.

    The volumes (of the solutions) to which you refer in your question are meaningless unless you also specify the concentration of the salts in those solutions.

    But just for grins, let us suppose that we had 700 mL of 1M CaCl2 solution and combined it with 300 mL of 1M Na2CO3 solution. (Your high and low volumes.) Since the greater volume of CaCl2 contained more moles of CaCl2, then the CaCl2 is in excess and some of the CaCl2 in the 700 mL of solution will be left, unreacted.

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