Homework Help Please - Geometry?

Question

Wow...

I've tried working this problem for a couple of hours and I still haven't got it yet!

Please help me

and tell me how you worked it out step-by-step if you can.

Q is in the interior of right angle PRS. If m anglePRQ is 4 times as large as m angleQRS, what is m anglePRQ?

Answer 1

For you to easily solve this qn, use already available info; ie You know that it's a right angle which means you have a 90 deg. Make the center of approach for the triangle be the 90 deg, ie Have angle PRS be 90. From there;

Let QRP = m

Then, PRS = QRS + QRP

                 = 4m + m

  But: PRS = 90°

∴　4m + m = 90°

            5m = 90°

              m = 90°/5

              m = 18°

∴PRQ = 4m = 4*18°

      = 72°

Answer 2

If it's a right angle than add the 2 sections and set it equal to 90 degrees.

x + 4x = 90

5x = 90

x = 18....angle QRS

4x = 72 degrees.....angle PRQ

Answer 3

i cant understand it by how you wrote it. im in geometry too :)

Answer 4

Call the smaller angle, QRS,  x.  Then the larger, PRQ, is 4x.  And they add up to 90 since the whole thing is a right angle.  

So x + 4x = 90

5x = 90

x = 90/5 = 18

so PRQ is 4•18 = 72