Honors geometry question?

Question

this is the problem:

angle 1 is congruent to angle 2

angle 1 equals x+14, and angle 2 equals y-3

solve for y in terms of x

my question is how do i do that??? i dont know what the textbook means by 'in terms of x', and our teacher never taught us that (today is only the 2nd day of school lol)

by the way, im looking for REAL HELP. i dont just want someone to give me the answer, thats pointless. i would really appreciate if someone could take the time to explain how to solve this problem for me. thanks :D

Answer 1

angle 1 is congruent to angle 2 ==> angle 1 = angle 2

angle 1 = x+14, angle 2 = y-3

==> x+14 = y-3

solve for y ==> x+14+3 = y-3+3

                      x+17 = y

solve for y in terms of x means you have to use x to express y.  

Answer 2

y in terms of x means that you solve for y.

for example if you had y + 2x = 4, you would subtract 2x from both sides to isolate the y, which gives y = 4 - 2x. now y is solved for in terms of x. It means you have solved for y but didn't get a numerical value, there are still variables(x) on the other side of the equation.

since there congruent set x + 14 = y -3

to solve for y (get the y alone) add three to both sides

x + 14 + 3 = y - 3 + 3

x + 17 = y

hope that helps

Answer 3

Well considering you have two different variables, theres really not much you can do hear, but the problem can be solved.

The problem starts out as the angles being congruent.

Thus, x+14=y-3

now, to get y by itself ( 'in terms of x means what will y equal when x equals something?) you need to add 3 to each side.

So, x+14+3=y

or, y=x+17

Answer 4

SAS (Side-Angle-Side): Two triangles are congruent if a pair of corresponding sides and the included angle are equal.

SSS (Side-Side-Side): Two triangles are congruent if their corresponding sides are equal.

ASA (Angle-Side-Angle): Two triangles are congruent if a pair of corresponding angles and the included side are equal.