Hooke’s law states that the distance a vertical spring stretches varies directly with the weight hanging from

Question

Hooke’s law states that the distance a vertical spring stretches varies directly with the weight hanging from it. A spring stretches 14 inches when a 35-pound weight is hanging from it. How much weight is needed to stretch the spring 54 inches?

17.6

135

43.6

21.6

Answer 1

x = k w

14 = k * 35

k = 14/35

54 = (14/35) w

w = 54 * 35/14

w = 135

So 135 pounds.