How apart are the vehicles at that time.?

Question

A car whose position is given by the equation d=25t+t^2 passes a police car that is travelling at 20m/s. The police officer turns on the siren and begins to accelerate at 1.5m/s^2 to chase the speeding car.

a) At what time the speeding moving at 31m/s

b)How fast is the police car movingat that time.

c)How far apart are the vehicles at that time.

d) Will the police car catch up the speeder? Explain.

Answer 1

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Answer 2

300 feet and closing the gap quickly at 37 mph--will catch up at another 265 feet--30 feet apart when contact is made.

Answer 3

huh