Question:

How can I solve this using dot product?

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1. Find angle BAC if A = (2, 2, 2), B = (4, 2, 1), and C = (2, 3, 1).

I have no idea how to draw the points on a 3 coordinate system.

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  1. BAC is the angel produce by vector AB & AC

    so

    AB=B-A= (4,2,1)-(2,2,2)=(2,0,-1)

    AC=C-A=(4,2,1)-(2,3,1)=(2,-1,0)

    &

    Angel BAC=arccos( (AB.AC)/(|AB|*|AC|) )

    =arccos( (4+0+0)/(square(5)*square(5)) )

    =arccos(4/5)

    =36.87


  2. cos Θ = AB 'dot' AC / [ |AB||AC| ]..AB = < 2,0,-1> & AC = < 0,1,-1>...about 1.25 radians...you don't need to plot the points if you use vectors...you could also use the cosine law from trig

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