Question:

How can i slove (logx)^2=9?

by  |  earlier

0 LIKES UnLike

How can i slove (logx)^2=9?

 Tags:

   Report

11 ANSWERS


  1. logx=the square root of 9 which is 3

    x=10^3=1000


  2. (logx)^2=9

    SQRT (logx)^2= SQRT 9

    logx = 3

    10^3 = x

    x = 1000

    Think that's right, hope it helps.

    Joe

  3. I think all answers are correct but missing one solution.

    if you take the squareroot of 9 then you should also account for -3 as a solution because -3 squared is 9.

    the extra solution is:

    log(x)=-3 => x=10^(-3), x=1/1000 check this answer and you will see that this is also a solution

  4. find the square root of both sides

    logx = 3

    then raise ten to the power of each side

    10^logx = 10^3

    the 10^log cancels so you're left with

    x=10^3

    x=1000

    that is assuming you aren't using natural logs

  5. logx = sqrt 9

    log x = 3

    x = 10^3

    x = 1000


  6. log x = 3

    x = 10³ (if logs are to base 10)

    x = 1,000

  7. (log x)^2 = 9

    log x = +-3

    x = 10^3 or x = 10^(-3)

    x = 1000 or x = 0.001

  8. (logx)^2 = 9

    logx = sqareroot(9)

    log x = 3

          x = 10^3     (the opposite of Log is 10^ )

           x = 1000


  9. Take the square root of both sides of the equation:

        log x = 3

    Then the inverse log of both sides:

        x = 1000

  10. log x= +-3 so x=10^3 =1000 or x= 10^-3 =1/1000

  11. Take the square root of both sides of the equation:

    log x = 3 ,-3(log can not be negative)

    so take logx=3

    Then x=10^3=1000

Question Stats

Latest activity: earlier.
This question has 11 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.
Unanswered Questions