How do I calculate force of gravity on a 1-kg at earth's surface? mass of earth, 6x10 to 24 kg, r is 6.4x10 t6

Question

How do I calculate force of gravity on a 1-kg at earth's surface? mass of earth, 6x10 to 24 kg, r is 6.4x10 t6

Answer 1

Using Newtons law of universal gravitation,

F=Gm1m2/r^2

where G is Gravitational constant = 6.67 x 10^-11

m1 is mass of 1 kg object = 1 kg :-)

m2 is mass of Earth = 6 x 10 ^24kg

r is radius of Earth = 6.4 x 10^6m

F=(6.67 x 10^-11)(1 x 6 x 10 ^24)/(6.4 x 10^6)^2

F=4.002 x 10^14/4.096 x 10^13

F=9.77 N

Hope this helps :-)

Answer 2

simple enuf. Here you go:

The input valve flow rate is 0.352 mL/min.  The output (1) flow rate is 0.336 mL/min.  Output (2) flow rate is 0.016 mL/min.  I want to evaluate dissolved [CO2] concentration flowing out of output(2) over 2 hours.  I know how input and output(1) [CO2] concentration vary with time... ([CO2] in mM/liter)

Hopefully you can read this (i = input, o = output (1))

(t=0: i = 1.28, o = 1.02) (t=20: i = 1.31, o = 0.85) (t=40: i = 1.34, o = 0.72) (t=60: i = 1.34, o = 0.69) (t=80,100,120: i = 1.34, o = 0.69)

Enjoy