How do I calculate the ratio and volume on my chemical sprayer?

Question

I have a new boom sprayer for my tractor and I was wondering how much chemical is to be sprayed.I plan to spray my fields with round-up before planting and I dont know how much i'm using or much much i will need...Any help will be appreciated

Answer 1

It's easy.  There are 43,560 square feet in an acre.  Just figure how much liquid your sprayer puts out to cover this area.     If you need to know how to determine how big your area is just measure the distance down the field and then across the field and multiply the two numbers.  Let's say you mark off the field for a 1/10 acre and your rig put out one gallon to cover that area.  Then fill your tank with 10 gallons and the chemical to cover the acre.  Just remember there are 43,560 square feet in an acre and you will figure it out!

Answer 2

Determine the gear and rpm that you will be using on your tractor while you are spraying.  Next mark off a set distance, say 1000 yards and check the time it takes you to travel the 1000 yards .  Put some water in your sprayer and start spraying at your predetermined rpm of your tractor.  Catch the water coming from one nozzle for the number of seconds it took you to travel the 1000 yards.  Multiply that volume by the total number of nozzles that you have. To get the square yards sprayed multiply 1000 yards by the width of your sprayer.  Now you know the volume sprayed per square yard and you can convert this to volume per acre.  If you find that the volume is more than you need, measure again at a faster speed or lower rpm.  Less than you need, try a slower speed or higher rpm.  It's not complicated, it just takes a little time.  The time you take to do this can save you a lot of money by spraying the correct amount Round Up.

Answer 3

Application Rate

A = liquid flow (nozzle output) for 1 minute

Nozzle Output/Flow rate  = [………………….] L/min           (A)

B = Area (Swath Width x Distance)

Width  =          [………………….]  

x

Distance Travelled  =          [………………….]

Width x Distance                =          [………………….] M²  (B)

C = APPLICATION RATE

A   ÷   B  x10 000 = [              ] L/ha

[……………]  ÃƒÂƒÃ‚·  […………]  x 10 000 = […………] L/ha

D = AMOUNT OF CHEMICAL TO ADD TO THE TANK

Spray Tank Size=[………………..] L

Application Rate=[………………..] L/ha

                                                (see above answer)

Chemical Rate=[………………..] L/ha

                                                 (Label Rate)

Tank Size  ÃƒÂƒÃ‚·  Application Rate x Chemical Rate = [.............] L

[……….]   ÷   [………….…] x [……….…] = [………..] L

Sorry, I only use metric.

Answer 4

get your self a users manual, also go to your local co-op they should be able to tell you.