How do I do the atoms/moles/mass conversion for the following?

Question

A. What is the # of atoms of sodium in 1.50 moles of sodium?

B. What is the mass in grams of 4.50 x 10^12 atoms of Chlorine?

C. The number of atoms in 1.50 g of potassium?

Answer 1

A.

1.50 moles Na x (6.02E23 atoms / 1 mole) = 9.03 x 10^23 atoms Na

B.

4.50E12 atoms Cl x (1 mole Cl / 6.02E23 atoms Cl) x (35.453g Cl / 1 mole Cl) = 3.65 x 10^-10 g Cl

C.

1.50g K x (1 mole K / 39.089g K) x (6.02E23 atoms / 1 mole) = 2.31 x 10^22 atoms

Answer 2

you have to use 6.022x10^23atoms in 1mol formula

A. 1.5mol(6.022x10^23)=9.033x10^23

B. (4.5x10^12)/(6.022x10^23)=7.258x10^-12mo...

C. 1.5g(1mol/39.1g)=.0384mol(6.022x10^23)=2...

make it a good day

Answer 3

Remember Avogadro

The number of elementary entities (atoms, molecules, ions or other particles) in one mole of a substance, 6.022142 x 10^23, is known as Avogadro's number.

To solve A, multiply A's number by 1.5

To solve B, calculate the number of moles of chlorine by dividing (4.5 x 10^12) by A's number, then multiply that by 35.4527, the atomic mass of chlorine.

To solve C, reverse the process of B - divide 1.50 by 39.0983, the atomic mas of potassium to get the number of moles and then multiply that number by A's number.

HINT. Since your input data is precise only to 3 significant figures, use only 4 figures of the other numbers.  Now you know how!

Answer 4

A. 1.50 moles Na x (6.02 x 10^23 atoms Na / 1 mole Na) = 9.03 x 10^23 atoms Na

B. 4.50 x 10^12 atoms Cl x (1 mole Cl / 6.02 x 10^23 atoms Cl) x (35.5 g Cl / 1 mole Cl) =

2.65 x 10^-10 g Cl

C. 1.50 g K x (1 mole K / 39.1 g K) x (6.02 x 10^23 atoms K / 1 mole K) = 2.31 x 10^22 atoms K

Answer 5

A. There are 9.03 atoms in 1.5 moles of sodium

B. 4.5 trillion atoms of chlorine makes up 2.65 x 10^-11 grams

C. There are 2.31 x 10^22 atoms in 1.5 grams of potassium