How do I find a general form equation for the line through the pair of points (-1,2) and (2,5) ?

Question

How do I find a general form equation for the line through the pair of points (-1,2) and (2,5) ?

Answer 1

find the slope first

5-2 over 2+1

3/3 or 1

y-5=1(x-2)

y-5=x-2

x-y=-3

Answer 2

this is the form your looking for:

y = mx + b

find the slope:

m = (y2 - y1) / (x2 - x1)

plug in one of the ys and corresponding x and the m you just found into the y = mx + b and solve for b.

Answer 3

all i remember is how u label them

(-1,   2)

^x1,  ^y1

(2,    5)

^x2,  ^y2

then u put them into that equation thingy your given,i forget wat its like.

sori  

Answer 4

Which form;

y=mx+b,

or ax +by +c=0

find your m (slope) using;

y2-y1/x2-x1.

5-2/2-(-1)

3/3

m=1

Find your b by substituting a point in for x,y (lets use -1,2)

y=mx+b

2=1(-1) +b

3=b

your general equation is

y=x+3

Answer 5

The slope between the points is 1.

y-intercept form y= mx+b

Plug in a point to figure out rest of equation

5 = (1)(2) + b

b=3

y-intercept form is y=x+3

standard form is x-y = -3

Point-slope form is (y-5) = (1)(x-2)

Answer 6

first, get the slope

m=Y2-Y1/X2-X1 * 2 and 1 are subscripts

m=5-2/2-(-1)

m=3/3

m=1

after getting the slope, use this:

Y-Y1=m(X-X1)

Y1 and X1 are any of the coordinates on your given

so, you can use either (-1,2) or (2,5)

ill use (2,5)

Y-5=1(X-2)

simplify

Y-5=X-2

isolate y

Y=X-2+5

Y=X+3

thats your equation of the line in the form y=mx+b

this will be your equation if its in the form ax+by=c

X-Y= -3

hope you understood