How do I find the equation of a line that goes through (k, -2) and is perpendicular to 8-3x=9y????????????????

Question

I'm having a lot of trouble with this one. Could you also show me how to do it rather than just giving me the answer? Tyvm.

Answer 1

well first divide the 3x=9y by three.

Then it should be x=3y

then divide that by three and it will be Y=1/3X

and that gives your the slope and equation of the line (start at k,-2 and go up one over three)

Start from (k,-2) and do the opposite, up three over one.

Sorry if this is confusing.

Answer 2

first, rearrange the equation:

y=-(1/3)x+(8/9)

Now, the formula for a line is y=mx+b

We know that the slope, if perpendicular, must be the inverse reciprocal of its perpendicular line.

So: y=3x + b

Now, simply plug and chug!

-2=3(k)+b

b=-2-3k

Therefore: y=3x-2-3k