How do I find the equivalent resistance of a series and parallel circuit?

Question

I'm given a picture of a series circuit in the shape of a square. Three sides have difference resistors in ohms, and the fourth side has a battery with a listed voltage. How do I find:

The equivalent resistance of a series curcuit?

The current leaving the battery?

The current through a resistor?

The voltage across a resistor?

The power dissipated by a resistor?

Also, how would I find these things in a parallel circuit?

Thanks in advance!

Answer 1

1) r1+r2+r3= rt

2)battery voltage/ rt

3)battery voltage/rt

4)battery voltage/rt X r

5)battery voltage/rt ^2 X r

Answer 2

Series: equivalent resistance = R1+R2+R3+...+Rn

Parallel: (1/equivalent resistance) = 1/R1+1/R2+1/R3+...1/Rn

To find current and voltage, use I=V/R

where R is the equivalent resistance.

Power = IV = V^2/R