Question:

How do I find the missing length of a triangle that is 50 and 48 ?

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New at doing algebra

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  1. you can use sine, cosine, tangent and pythagoros theorem if triangle is right-angled otherwise information is not enough. You must know atleast one angle of the triangle.


  2. You can't find the length of a third side if you have the length of the other two.  

    Think about it, if you have a side that is 50 and one that is 48 you can put a third side between them that is 3 inches, or 4, or 8, or 16, or 32, etc.

    Now, knowing an angle or two helps, but that is a different question.

  3. the pathagorean theorm

    a^2 +b^2 = c^2

  4. Trigonometry.  Use SOH CAH TOA.  

    Sign-opposite over hypotenuse

    cosign-adjacent over hypotenuse

    tangent- opposite over adjacent

    Then just use a proportion to solve.  

  5. You can not get an single answer based upon the information given.  

    It could be anything from a very acute triangle with the third side being the most minute fraction over 2 to an incredible obtuse triangle with the third side being the most minute fraction under 98.   Meaning you have infinite answers.

    If it is a right triangle you still can not calculate it because you did not state if the measurements given are the sides or one side and the hypotenuse.  

    If they are the sides,  then the hypotenuse is about 69.6 inches long.   If one is the side and the other the hypotenuse then the other side is 14 inches.  Since the second calculation comes out to an even number,  I would go on the assumption that is your answer and what you gave us was the hypotenuse of 50 and the first side of 48,  leaving the second side of 14.  

    Next time give all the information and make it easier on those trying to answer the question.....K?

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