Question:

How do I find the perimeter of a right-angled triangle?

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One side is 8.3cm and another is 7.7.. I know from the answers that is it 27.3..But how do I get that answer ???

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  1. use the pythagorean theorem,find first the other side of it

    c2=a2+b2

    and then when you find the other side

    add all sides that's the perimeter


  2. Its simple........................just add the length of the 3 sides of the triangle.............................sel... my answer as the best

  3. Well if it's right angled you can use Pythagoras's theorem:

    Let's say your triangle looks like this:    

    ..._Y_

    X|..../ Z

    ..|.../

    ..|../

    ..|./

    ..|/

    Then Z*Z=X*X + Y*Y. This is valid for all right-angled triangles

    So to find the perimeter all you have to do is to sum up all 3 sides. You already know to of them, and the 3rd one can be calculated using the above formula. Z*Z=8.3*8.3 + 7.7*7.7=68.69+59.29=128.18. To find Z you need to find the square root of 128.18 witch is approximately  11.3. The perimeter is 11.3+7.7+8.3=27.3

    BINGO

  4. The perimeter is the sum of the legs and the hypotenuse. You calculate the hypotenuse using the Pythagorean theorem.

    The Pythagorean theorem states that the square of the hypotenuse is the sum of the squares of the legs, or more usefully,

    c = sqrt( a ^ 2 + b ^ 2 )

    So, your perimeter may be calculated as

    p = a + b + c

    p = 8.3 + 7.7 + sqrt( 8.3 ^ 2 + 7.7 ^ 2 )

    p = 27.3216606555752

  5. Hyp is given by pythogras theorem

    A^2+B^2 = C^2

    8.3^2  +  7.7^2  = C^2

    C^2  = 128.18

    C = 11.3

    perimeter  A+B+C

                  8.3+7.7+11.3  = 27.3

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