How do I find the steady state current in a RLC circuit with no initial conditions?

Question

Given R, L, C, and E but no initial conditions. Please help. This is for my Math class.

Answer 1

E/R  

  the L and C do not contribute steady state current

Answer 2

You also need frequency f or radian frequency ω.

Math would approach it as a complex number calculation and as a series circuit.

X_L = 2 π f L = ωL

X_C= 1/[2 π f C] = 1/[ωC]

Z = R + j (X_L - X_C)  ÃƒÂ¢Ã‚‡Â’ complex calculation

I = E/Z ⇒ complex calculation

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Can also be done without complex numbers.

X_NET = X_L - X_C

Z = √(R^2 + X_NET^2)

I = E/Z

Have fun...

Answer 3

In general, from an engineering standpoint, we say that the system is at steady state after a time period of five time constants.

You will need to use a second order solution to find your result, try the link to see the process.

Parallel RLC Circuits are easier to solve in terms of current. Series RLC circuits are easier to solve in terms of voltage.

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