How do I find the x and y intercepts in a fraction equation?

Question

The problem is:

y=(2x-1)/(3-x)

How would I go about doing this? I'm totally stuck on my homework.

Answer 1

for the y-intercept, x = 0

this gives you (0 - 1) / (3 - 0) = -1/3

so the y-intercept is (0 , -1/3)

for the x-intercept, y = 0 , which happens when the numerator is 0

therefore: 2x - 1 = 0

x = 1/2

x-intercept: (1/2 , 0)

Answer 2

Let x = 0 and solve.

y = -1/3 (y-intercept)

Let y = 0 and solve.

0(3-x) = 2x -1

0 = 2x - 1

1 = 2x

1/2 = x

So, y-intercept is (0, -1/3) and x-intercept is (1/2, 0)

Answer 3

Let x = 0 then calculate y,

Let y = 0 then calculate x.

No matter fraction or not,

That is how intercepts are found.

Answer 4

To find the y-int substitute 0 in for x, then solve for y.

To find the x-int substitute 0 in for y, then solve for x.

I'll do the first

y=(2x-1)/(3-x)

y = (2(0)-1)/(3-0) = -1/3

So the y intercept is (0,-1/3)

Try the x intercept using the guidelines above.

Hope this helps!