How do I get an array of char* in C++?

Question

I am trying to store a whole bunch of char* strings in an array, but I forget how to dynamically initialize an array of char*, can anyone help me?

Am I supposed to do

char** headerArray = new char*[headerCount];

for(int i=0;i<headerCount;i++)

headerArray[i] = new char*[MAX_LENGTH];

????

Answer 1

Yes, you are correct (you must use a loop)

Answer 2

remember the main (int argc, char *argv[]), that argv is the array of char *;

Wish the following code will be helpful,

---

int max = 100;

char s2a [max][max];

for (int i=0; i &lt; max; i ++){

    strcpy (s2a[i], &quot;abc&quot;);

}