How do I rearrange the formula to make L the subject?

Question

M= wx(L-x) / 2

I got the answer L= 2M+ wx but i think its wrong...

Answer 1

I guess you mean to solve for L....

M = wx(L - x) / 2

First multiply by 2...

2M = wx(L - x)

then divide by wx...

(2M)/(wx) = L - x

then add x to both sides...

L = (2M)/(wx) + x

Answer 2

2 M / w x = L - x

L = x + 2 M / w x

Answer 3

M = wx(L - x)/2

2M = wx(L - x)

L - x = 2M/wx

L = 2M/wx + x

Answer: L = 2M/wx + x or L = (2M + wx²)/wx

Answer 4

Hi i got a different answer:

M=wx(L-x)/2

multiply each side by 2

2M=wx(L-x)

Divide by wx

2M/wx=L-x

add x

2M+x/wx

Thats how I would rearrange the equation, you can't seperate wx(L-x) without dividing them because it's actually wx multiplied by (L-X).

Answer 5

2M = wx (L - x)

2M/wx = L - x

2M/wx + x = L

Rearranging the equation,

L = 2M/wx + x

Answer 6

(2M/wx) + x = L

Answer 7

First step --- multiply both sides by 2

2M = wx(L - x)

Second step -- divide both sides by "wx"

(2M)/(wx) = L - x

Third step -- add "x" to both sides of the equation

(2M)/(wx) + x = L - x + x

Rearrange the above,

L = [(2M/(wx)] + x

Hope this helps.