How do I solve for X in this equation?

Question

(5/3)(x-7) = (2/5)x +1

I have no idea how to get rid of the coefficient fractions. Help?

Answer 1

5x/3 - 35/3 = 2x/5 + 1

5x/3 - 2x/5 = 1 + 35/3

19x/15 = 38/3

x = 38/3 x 15/19

x = 10.

Answer 2

multiply both sides by the LCD, 15.

5(5)(x - 7) = 2(3)x + 15

25x - 175 = 6x + 15

19x = 190

x = 10

hope this is correct.. :)

Answer 3

Suppose you were to multiply both sides of your equation by the same number.  Would you still have an equation ?  What number could you choose ?  Would 15 be interesting ?

Don' t forget that you have to multiply each term.

I hope you know the difference between terms and factors.

Anyone who knows about coefficients should know these things.

Good luck.

Answer 4

Let's try this out, it's a little hard doing it on computer though.

5/3(x-7) = x * 5/3 - 7 * 5/3 = 5x/3 - 35/3  

(2/5)x + 1 = 2x/5 +1

(5/3)(x-7) = (2/5)x +1             =        5x/3 -35/3 = 2x/5 +1

5x/3 -35/3 + 35/3 = 2x/5 +1 +35/3

5x/3 = 2x/5+1 +35/3

5x/3 -2x/5 = 2x/5 - 2x/5 +1 +35/3

5x/3 -2x/5 = 1 +35/3

5 * (5x/3) - 3(2x/5) = 1 + 35/3        Multiplied to get common denominators

25x/15 - 6x/15 = 1 +35/3       (35/3 is also 11 2/3)

19x/15 = 1 + 11 2/3 = 12 2/3

x(19/15) = 12 2/3

x(1.26) = 12 2/3

x(1.26) / 1.26 = (12 2/3) / 1.26

x = 10

Tadah!

Answer 5

5/3(x-7)=(2/5)x+1

opening bracket.

5x/3-35/3=2x+5/5

5x-35/3=2x+5/5

cross multiplication.

5(5x-35)=3(2x+5)

25x-175=6x+15

25x-6x=15+175

19x=190

x=190/19

x=10.