How do I solve this problem: (x+2)(x-99)=0 ?

Question

I don't think it's foiling....

somebody please help me!

Answer 1

It's factored out already. Let's start with the first quantity.

(x+2)

-2 plugged in as x would make it equal zero. (-2+2)=0.

The first solution is -2.

(x+99)

-99 plugged in as x would make it equal zero. (-99+99)=0

The second solution is -99.

The two answers are -2 and -99...I hope I explained it well!

Answer 2

what you have to do is get a value for x.

first you separate them:

x+2=0 & x-99=0

for x+2=0 you have to get x by itself so you subtract it from both sides.

so your value is -2

for x-99=0 you have to get x by itself so you subtract it from both sides.

so your value is 11

so you have:

x=11

&

x=-2

Answer 3

yes it is foiling...thats all u gotta do

Answer 4

x+2=0 ---> x= -2                

X-99=0-----> x= 99

Answer 5

First distribute the parentheses.

(x+2)(x-99)- so you do x times x which is xsquared, then x times 99 which is 99x, then 2 times x which is 2x and finally 2 time 99 which is  198. so it comes out like this x2(squared)+99x+2x+198=0.

you add the common ones and  end up with: x2+101x+198=0.

This is a quadratic equation which means there will be 2 answers.

(x+99)(x+2)=0

x= -99 and x= -2

Answer 6

no u use the zero property

either x+2=0 or x-99=0

solve each of these for x and u have yr answers