Question:

How do I use the half-angle formula to solve this triangle?

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I need to solve the following case III triangle using the half-angle formula, here is the triangle

a = 27, b = 21 and c = 24

I am using a skeleton solution so it would be of great help if your answers were in that form. Here is what I've done so far.

Skeleton Solution

a = 27

b = 21

c = 24

2s = 72

s = 36

s-a = 9

s-b = 15

s-c = 12

log (s-a) = 0.95424

log (s-b) = 1.17609

log (s-c) = 1.07918

3.20951

log s = 1.55630

2) 1.65321

log r = 0.82660

log r = 0.82660

log (s-a) = 0.95424

log tan A/2 = ?

A = ?(in form of degrees, min, and sec)

log r = 0.82660

log (s-b) = 1.17609

log tan B/2 = ?

B = ?(degrees, min, and sec)

log r = 0.82660

log (s-c) = 1.07918

log tan C/2 = ?

C = ?(degrees, min, and sec)

I know that tan A/2 = r/s-a, but it doesn't add up for me. Please correct me on any errors you find, I'm sure there are many. Thanks for the help!

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1 ANSWERS


  1. er........... wonder why u went thru all that!

    simple formula (extension of phytogoras theorm)

    a^2=b^2+c^2-2bcCosA

    cycle the values to get other angles

    hope u can caluculate now

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