I need to solve the following case III triangle using the half-angle formula, here is the triangle
a = 27, b = 21 and c = 24
I am using a skeleton solution so it would be of great help if your answers were in that form. Here is what I've done so far.
Skeleton Solution
a = 27
b = 21
c = 24
2s = 72
s = 36
s-a = 9
s-b = 15
s-c = 12
log (s-a) = 0.95424
log (s-b) = 1.17609
log (s-c) = 1.07918
3.20951
log s = 1.55630
2) 1.65321
log r = 0.82660
log r = 0.82660
log (s-a) = 0.95424
log tan A/2 = ?
A = ?(in form of degrees, min, and sec)
log r = 0.82660
log (s-b) = 1.17609
log tan B/2 = ?
B = ?(degrees, min, and sec)
log r = 0.82660
log (s-c) = 1.07918
log tan C/2 = ?
C = ?(degrees, min, and sec)
I know that tan A/2 = r/s-a, but it doesn't add up for me. Please correct me on any errors you find, I'm sure there are many. Thanks for the help!
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