How do i calculate the pH of a mixture formed by adding the following...

Question

formed by adding 45.0 mL of 2.5×10^−2 M HCl to 140 mL of 1.0×10^−2 M HI. The M here is Molarity.

Answer 1

just get the total mmoles of H+  from the two strong acids HCl and HI and divide by the total volume and that will be mmoles/mL = M  then take -log M = pH

soo 45 X 0.025 M = 1.125 mmoles H+

140 mL X 0.01 M =  1.400 mmoles   th3 total mmols is  2.525 and the total volume is 185 mL  so the molarity of the solution is 2.525/185 mL = 1.36 X 10^-2   so pH = 2 - log 1.36 =  1.87