How do i do limiting reaction? ?

Question

2naoh+co2=na2co3+h20

which reagent is the limiting when 1.85 mol naoh and 1.00 mol co2 are allowed to react? How many moles of Na2co3 can be produced? how many moles of the excess reactant remain after the completion of the reaction?

Answer 1

this : 2naoh+co2=na2co3+h20  shows that they have to add twice the # of moles of NaOH , as they add  moles of CO2

but they didn't do that, so

your answer is NaOH is the limiting reagent

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the reaction is "limited by the amount of NaOH:

2 moles NaOH --> 1 mole of Na2CO3  (2:1 RATIO),.... so

1.85 moles NaOH --> 1/2 it--> produces 0.925 moles Na2CO3

your answer is : you can produce 0.925 moles of Na2CO3

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again with the ratio, 2 mole NaOH  & 1 mole CO2 --> (2:1 ratio)

1.85 moles NaOH --> 1/2 it--> reacts with 0.925 moles CO2

out of 1.00 moles to start with , that leaves:

your answer: 0.075 moles of CO2 remaining after the reaction