How do i do these algebra 1 problems? (like terms)?

Question

im really poor in like terms but u guys can turn that around whoever explains better will get 10 points. thanks

1.) -6x-1-14x= -14x - 4 + 11x - 5

2.) x-2(x-5) = -6-(5x+4)

Answer 1

Like terms mean having the same variable expressions or constant expressions in common.

Example:

1) -6x - 1 - 14x = -14x - 4 + 11x -5

Like terms here are -6x, -14x, -14x, and 11x

Also, all of the constants (numerical values) are also considered like terms: -1, -4, -5

So, here's how to solve the first equation:

-6x - 1 - 14x = -14x - 4 + 11x -5

1. Place all like terms side by side.

-6x -14x -1 = -14x + 11x -4 - 5

2. Transpose all x terms on one side of the equation, and all constants on the other side. Remember when you transpose, the signs change:

-6x - 14x + 14x - 11x = -4 -5 + 1

3. Combine (in this case add) all like terms: The -14x and +14x cancel out because they add up to 0. Add -6x and -11x. Then, do the same with the right side of the equation:

-17x = -8

4. Divide both sides of the equation by -17 to solve for x:

x = 8/17.

I'll do number 2 quickly, since the explanation would be the same:

2.

x-2(x-5) = -6-(5x+4)

x - 2x + 10 = -6 - 5x -4

-x + 5x = -20

4x = -20

x = -5

Answer 2

super easy.   just add everything that is alike, and change the sign when you cross the =

1)  -6x-14x+14x-11x=-4-5+1

-17x=-8

x=-8/-17

x=8/17

Remember on this one distribute the factor on the outside of the parentheses

2) x-2x+10=-6-5x-4

x-2x+5x=-10-6-4

4x=-20

x=-20/4

x= -5