How do i find z in this: 3(z+4)+2(z-3)=26 ?

Question

How do i find the z in this equation : 3(z+4)+2(z-3)=26

and please tell me how to work it out and whats the answer , i need it desperately

Answer 1

1) distribute 3 to (z+4), distribute 2 to (z-3)

3z+12+2z-6=26

2) combine like terms

5z+6=26

3) subtract 6 to the right side

5z = 20

4) divide by 5

z=4

Answer 2

z=4.

open the equation - 3z + 12 +2z -6 = 26

therefore 5 z +6 = 26

therefore 5z=20

therefore z = 4

AM

Answer 3

4

Answer 4

3(z+4)+2(z-3)=26

3z+12+2z-6=26

5z+6=26

5z=20

z=4

Answer 5

3(z+4)+2(z-3)=26

multiply to get rid of parenthesis

3z+12+2z-6=26

combine like terms

5z+6=26

solve for z

5z=20

z=4